An unknown resistance R 1 is connected in series with a resistance of 10 Ω Ω . This combinations is connected to one gap of a meter bridge while a resistance R 2 is connected in the other gap. The balance point is at 50 cm. Now, when the 10 Ω Ω resistance is removed the balance point shifts to 40 cm. The value of R 1 is (in ohm)
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For first balancing condition $\frac{10 + R_{1}}{R_{2}} = \frac{50}{50}$
⇒ ⇒ $R_2 = 10 + R_1$ . For second balancing condition $\frac{R_1}{R_2} = \frac{40}{60}$
⇒ ⇒ $\frac{R_1}{10 + R_1} = \frac{2}{3}$
⇒ ⇒ $R_1 = 20 \, \Omega$
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